Hsngxg Axg Xx
Also können wir schreiben p(x)=x2 1 =(x−i)(xi) Ist wieder f(x)=a nxna 1xa 0, so können wir nach dem undamenF talsatz immer eine Lösung x 1 von f(x)=0 nden, also nach Satz 2 einen Linearfaktor (x−x 1)von f(x)abspalten und ein Restpolynom t(x) bekommen, dessen höchster Koe zient wieder a n ist und für das degt= n−1 ist Auf die Weise können wir den Grad des.
Hsngxg axg xx. S A X x X g K c ̃ N W ł. Vertical Translation For the base function f (x) and a constant k, the function given by g (x) = f (x) k, can be sketched by shifting f (x) k units vertically Horizontal Translation For the base function f (x) and a constant k, the function given by g(x) = f (x k), can be sketched by shifting f (x) k units horizontally Vertical Stretches and Shrinks.
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