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Gxjm s aj. Thus, j(f g)(x)j M 1M 2 for all x 2R Therefore, f g is bounded, with M = M 1M 2 as a bound (c) If f g is bounded, then so are f and g FALSE Counterexample Let f and g be de ned by f(x) = x and g(x) = x for all x Then (f g)(x) = f(x) g(x) = x ( x) = 0 for all x, so f g is bounded, while neither f nor g are bounded (d) If fg is bounded, then so are f and g FALSE.
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